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e) 8 + 4x{3+ 3x[r + 4x(x:2 + 2)]:6}:31 = 12​

Răspuns :

8 + 4*{3+ 3*[r + 4*(r:2 + 2)]:6}:31 = 12

4*{3+ 3*[r + 4*(r:2 + 2)]:6}:31 = 12 - 8 = 4

4*{3+ 3*[r + 4*(r:2 + 2)]:6}:31 = 4. Rezulta

{3+ 3*[r + 4*(r:2 + 2)]:6}:31 = 1

3+ 3*[r + 4*(r:2 + 2)]:6 = 31

3*[r + 4*(r:2 + 2)]:6 = 31 - 2 = 28

[r + 4*(r:2 + 2)]:2 = 28

[r + 4*(r:2 + 2)] = 28 * 2 = 56

r + 4*(r:2 + 2) = 56

r + 4 r / 2 + 8 = 56

r + 2 r = 56 - 8 = 48

3 r = 48

r = 16