2011 spec. Va rog frumoas.

Răspuns:
3x+2/x+1∈Z=> x+1|3x+2
x+1|x+1 |*3
<=>x+1|3x+2
x+1|3x+3 <=> x+1|3x+3-(3x+2)<=>x+1|1=> x+1∈D₁={-1, 1}|-1
x∈{-2, 0}
A={-2, 0}