[tex]\it m(\widehat{ACB})=180^o-128^o=52^o\ (suplementul\ lui\ 128^o)\\ \\ ABC-isoscel,\ AB=AC\Rightarrow m(\widehat{ABC})=m(\widehat{ACB})=52^o[/tex]
[tex]\it [BE\ -\ bisectoare \Rightarrow m(\widehat{EBC})=\dfrac{52^o}{2}=26^o[/tex]
[tex]\it (\widehat{AEB})=\ unghi\ exterior\ triunghiului\ EBC \Rightarrow m(\widehat{AEB})=m(\widehat{EBC})+m(\widehat{BCE})=\\ \\ = 26^o+52^o= 78^o[/tex]
