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Am nevoie de ajutor!!!


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Răspuns :

[tex]\it \dfrac{\sqrt{1225}}{\sqrt{441}}\cdot(\sqrt{225})^{-1}=\dfrac{35}{21}\cdot 15^{-1}=\dfrac{35}{21}\cdot\dfrac{1}{15}=\dfrac{35^{(5}}{21\cdot15}=\dfrac{7^{(7}}{21\cdot3}=\dfrac{1}{3\cdot3}=\dfrac{1}{9}[/tex]