Răspuns:
CH3-C(CH3)=C(CH3)-CH3+2O---> 2CH3-CO-CH3 Ori 1a moli
CH3-CH(OH)-CH3+O.-----> CH3-CO-CH3 ORI 2a moli
total moli propanona: 2a+2a=4a
dar 4a=0,8---> a=0,2mol
amestecul initial contine 0,2mol 2,3-dimetil-2 butena si 0.4mol 2-propanol
m,amestec= 0,2xM,....butena+0,4xM,2-propanol
calculeaza cele doua mase molara si, apoi, m,amestec !
Explicație: