Răspuns:
Explicație:
-se afla nr. de moli de Al
1mol Al-------------------6,023.10²³ atomi de Al
xmoli----------------------48,176.10²³ atomi Al
x=48,176.10²³ : 6,023.10²³=8 moli [ aproximativ 8]
1/2 =4moli Al
1/4=2moli Al
1/4=2moli Al
b.
4moli ymoli
2Al + 6HCl= 2AlCl3 +3H2
2moli 2moli
y=4 .2 : 2=4moli AlCl3
2moli zmoli
2 Al +3 Cl2 =2Al Cl3
2moli 2moli
z=2 . 2 : 2=2moli AlCl3
2moli + 4moli= 6moli AlCl3
-se afla masa totala de AlCl3
MAlCl3=27 + 3.35,5=133,5-------->133,5 g/moli
m=6moli . 133,5g/moli=801 g AlCl3
c.
2moli wmoli
2Al + Fe2O3 = Al2 O3 +2 Fe
2moli 2moli
w=2 . 2 : 2=2moli Fe
m=n.M
m=2moli .56g/moli=112g Fe
