Răspuns:
Explicație pas cu pas:
MVA, multimea valorilor admisibile,
[tex]\left \{ {{x-3>0} \atop {x-1>0}} \right. ~\left \{ {{x>3} \atop {x>1}} \right. ~deci~x>3.[/tex]
Suma logaritmilor in aceeasi baza este logaritmul produsului, deci
[tex]log_{2}[(x-3)(x-1)]=3,~deci~(x-3)(x-1)=2^{3},~x^{2}-x-3x+3=8,~x^{2}-4x+3-8=0,~x^{2}-4x-5=0,~delta=16+20=36>0,~\sqrt{delta}=\sqrt{36}=6,~deci\\x_{1}=\frac{4-6}{2}=\frac{-2}{2}=-1,~nu~apartine~la~MVA\\x_{2}=\frac{4+6}{2}=\frac{10}{2}=5~apartine~la~MVA[/tex]
Deci ecuatia are o solutie x=5