Răspuns:
Explicație pas cu pas:
[tex]a)\frac{2}{3}+\frac{4}{3}\cdot\frac{3}{2} = \frac{2}{3}+2 = \frac{2}{3}+\frac{6}{3} = \frac{8}{3}\\ b)\frac{19}{6}-\frac{5}{18}\cdot3 =\frac{19}{6}-\frac{5}{6} = \frac{14}{6}=\frac{7}{3}\\ c)\frac{3}{4}\cdot\frac{5}{6}+\frac{1}{4}=\frac{5}{8}+\frac{1}{4}=\frac{5}{8}+\frac{2}{8}=\frac{7}{8}[/tex]