a)
[tex]\it \dfrac{1}{6}+\dfrac{^{2)}1}{\ 3}= \dfrac{1}{6}+\dfrac{2}{6}=\dfrac{1+2}{6}=\dfrac{\ 3^{(3}}{6}=\dfrac{1}{2}[/tex]
Acum, a) devine:
[tex]\it \Big(\dfrac{1}{2}-\dfrac{1}{2}\Big)^{100}=0^{100}=0[/tex]
d)
[tex]\it 2\dfrac{1}{2}=\dfrac{5}{2}[/tex]
Acum se poate scrie:
[tex]\it \Big(\dfrac{5}{2}\Big)^{15}:\Big(\dfrac{5}{2}\Big)^{10}:\Big(\dfrac{5}{2}\Big)^{4}=\Big(\dfrac{5}{2}\Big)^{5}:\Big(\dfrac{5}{2}\Big)^{4}=\dfrac{5}{2}[/tex]
