Răspuns:
[tex]a)x=\sqrt{6}[/tex]
[tex]b)x=1[/tex]
[tex]c)x=\sqrt{3}[/tex]
[tex]d)x=\frac{3.5}{-2.5}[/tex]
[tex]e)x=\sqrt{45}[/tex]
[tex]f)x=\frac{1}{5}[/tex]
[tex]g)x=\sqrt{\frac{81}{18} }[/tex]
[tex]h)x=0[/tex]
Explicație pas cu pas:
a) [tex]x+\sqrt{2} =\sqrt{8} =(x+\sqrt{2} )^2=(\sqrt{8} )^2=x^2+2=8|-2=x^2=6,x=\sqrt{6}[/tex]
[tex]b) 4.5*x+9=13.5|-9=4.5*x=4.5|:4.5=\frac{4.5}{4.5} *x=\frac{4.5}{4.5} =1*x=1,x=1\\\\c) \sqrt{3} *x-2=1|+2=\sqrt{3} x=3=(\sqrt{3}x)^2=(3)^2=3x^2=9|:3=\frac{3x^2}{3} =\frac{9}{3} =x^2=3,x=\sqrt{3}[/tex]
[tex]d)-3\frac{1}{2} *x-1.5=\sqrt{2} ^2=\frac{-5}{2} x-1.5=\sqrt{2}^2= -\frac{5}{2} x-1.5=\sqrt{2^2} =-2.5x-1.5=\sqrt{4} =-2.5x-1.5=2|+1.5=-2.5x=3.5|:-2.5=\frac{-2.5}{-2.5} x=\frac{3.5}{-2.5} =\frac{1}{1} x=\frac{3.5}{-2.5} ,x=\frac{3.5}{-2.5}[/tex]
[tex]e) \frac{x}{\sqrt{3} } +\sqrt{12} =\sqrt{27} ,(\frac{x}{\sqrt{3} } )^2+(\sqrt{12} )^2=(\sqrt{27} )^2,\frac{x^2}{3} +12=27|-12,\frac{x^2}{3} =15|*3,x^2=45,x=\sqrt{45} \\\\f) x*\sqrt{5} -\frac{1}{\sqrt{5} } =0,x(\sqrt{5} )^2-\frac{1}{(\sqrt{5} )^2} =0,x*5-\frac{1}{5} =0,5x-\frac{1}{5} |*5=0,25x-\frac{5}{25}=0 ,25x-\frac{1}{5}=0 |:5,\frac{25x}{5}-\frac{1}{\frac{5}{5}}=0,5x-\frac{1}{1} =0,5x-1=0|:5,\frac{5x}{5} -\frac{1}{5} =0,x-\frac{1}{5} =0|+\frac{1}{5} ,x=\frac{1}{5}[/tex]
[tex]g)\sqrt{18} *x+9=0|-9,\sqrt{18} x=-9,(\sqrt{18}x )^2=(-9)^2,18x^2=81|:18,\frac{18x^2}{18} =\frac{81}{18} ,x^2=\frac{81}{18} ,x=\sqrt{\frac{81}{18} }[/tex]
[tex]h)\sqrt{24} *x=0,\sqrt{24} x=0,(\sqrt{24x})^2=(0)^2,24x^2=0|:24,\frac{24x^2}{24} =\frac{0}{24} ,x^2=0,x=\sqrt{0} ,x=0[/tex]
Sper ca te-am ajutat! Succes! :)
