Răspuns:
Explicație pas cu pas:
Fractia este supraunitara, daca numarator>numitor, deci
a) 5>x-1, ⇒5+1>x, ⇒6>x, ⇒x<6. x∈N, deci x∈{0,1,2,3,4,5}
b) 9>x+7, ⇒9-7>x, ⇒2>x, deci x<2, deci x∈{0,1}
c) 12>x+5, ⇒12-5>x, ⇒7>x, deci x<7, deci x∈{0,1,2,3,4,5,6}
d) x-7>9, ⇒x>9+7, ⇒x>16, deci x∈{17,18,19,20,...}
e) 5x+2>3x+4, ⇒5x-3x>4-2, ⇒2x>2, ⇒x>1, deci x∈N\{0,1}