Răspuns:
fie a,b,c laturile ∆.
Vom avea:
{a,b,c} dp {2,5,6}=>
a/2=b/5=c/6=K=>
a=2K (1)
b=5K (2)
c=6K (3)
a+b+c=65 (4)
(1)+(2)+(3)+(4)=>2K+5K+6K=65=>13K=65/:13=>K=5
Daca K=5 putem afla a,b,c din ce am scris la (1),(2) si (3)
a=2K (5)
K=5 (6)
(5)+(6)=>a=10
b=5K=>b=25
c=6K=>c=30
Verificare: a+b+c=65
10+25+30=65=>65=65(Adevarat)
Sper ca te-am ajutat :)
