Răspuns:
[tex]-6<a<3[/tex],a={0,1,2}
Explicație pas cu pas:
[tex]\frac{a+3}{a+6} <\frac{2}{3} |-\frac{2}{3} \\\\\frac{a+3}{a+6} -\frac{2}{3} <0\\\\\frac{a-3}{3(a+6)} <0|*3\\\\\frac{3(a-3)}{3(a+6)} <0*3\\\\\frac{a-3}{a+6} <0\\[/tex]
[tex]-6<a<3\\[/tex]
a={-5,-4,-3,-2,-1,0,1,2}, pastram doar nr. naturale
a={0,1,2}
Succes! :)
