Explicație pas cu pas:
Triunghiurile asemena au laturile direct proportionale
[tex] \frac{ab}{de} = \frac{bc}{ef} = \frac{ac}{df} \\ \frac{6}{de} = \frac{8}{ef} = \frac{10}{df} \\ a) \: df= 15 \\ \frac{6}{de} = \frac{8}{ef} = \frac{10}{15} = k = > k = \frac{2}{3} \\ \frac{6}{de} = k = > \frac{6}{de} = \frac{2}{3} = > de = 9 \\ \frac{8}{ef} = k = > ef = 12 \\ p = 9 + 12 + 15 = 36 \\ b)de = 1.5 \\ \frac{6}{1.5} = \frac{8}{ef} = \frac{10}{df} = k = > k = 4 \\ ef = 2 \\ df = 2.5 \\ p = 1.5 + 2 + 2.5 = 6[/tex]
