Răspuns:
[tex]\left \{ {{2(y+3)-4(x+1)=8} \atop {2(x+y+1)-3(y+2x+1)=0}} \right.[/tex]
[tex]\left \{ {{2y+6-4x-4=8} \atop {2x+2y+2-3y-6x-3)=0}} \right.[/tex]
[tex]\left \{ {{2y-4x=6} /:2 \atop {-4x-y=1}} \right.[/tex]
[tex]\left \{ {{y-2x=3} \atop {-y-4x=1}} \right.[/tex] +
/ -6x=4 /:(-2) 3x=-2 ⇒ x=[tex]-\frac{2}{3}[/tex]
y -2([tex]-\frac{2}{3}[/tex])=3 y+ [tex]\frac{4}{3}[/tex] =3 /*3 3y+4=9 3y=5 ⇒ y= [tex]\frac{5}{3}[/tex]
Explicație pas cu pas: