Răspuns:
aducem la acelasi numitor (prima ex cu 3, a doua cu 2)
[tex]\left \{ {{x+y+9y=14} \atop {2x+3y-4x-2y=0}} \right.[/tex] => [tex]\left \{ {{x+10y=14} \atop {y-2x=0}} \right.[/tex]
y-2x=0=> y=2x inlocuim in prima ec
x+20y=14 => 21y=14 => y=2/3
x= 4/3
