Răspuns:
Explicație:
9,2 kmoli NO2
MNO2= 14 + 2.16=46-----> 46g/moli
9,2kmoli= 9200 moli NO2
m =9200moli .46g/moli=432200 g NO2
46g NO2---------14g azot
432200g----------------x
x=432200.14 :46=128800g azot=128,800 kg
5moli AgCl
m=5moli.133,3g/moli=667,5 g AgCl
MAgCl= 108 +35,5=133,5-----> 133,5g/moli
133,5 g-----------35,5 g clor
667,5g--------------y
y=667,5 . 35,5 : 133,5=177,5 g clor
12moli H2SO3
mH2SO3= 12moli.82g/moli=984 g H2SO3
MH2SO3=2 +32 +3.16=82---->82g/moli
82g H2SO3--------2gH
984g------------------z
z=984. 2 : 82=24 g hidrogen
verifica calculele!
