(a-√3-√2)² +(b-√3+√2)²=0
(a-√3-√2)²≥0
(b-√3+√2)²≥0
suma lor fiind 0=> fiecare paranteza =0
a-√3-√2=0=> a=√3+√2
b-√3+√2=> b=√3-√2
media aritmetica=(a+b)/2
=(√3+√2+√3-√2)/2=2√3 / 2=√3
media geometrica=√(a·b)
=√[(√3+√2)(√3-√2)]= √(3-2)=1
media armonica=2ab/(a+b)
=2(√3+√2)(√3-√2)/ (√3+√2+√3-√2)
=2(3-2)/(2√3)
=1/√3
=√3/3
