Răspuns:
a) <AOB+<BOC=<AOC=180°
<AOB=x°
<BOC=y°
x/2=y/3=k
(x+y)/(2+3)=k
180/5=k
k=36
x/2=36=>
x=72°
y/3=36
y=36*3
y=108°
<AOB=72°
<BOC=108°
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<AOE=<AOB+<BOE
Deoarece OE bisectoare
<BOE=<BOC/2=108/2=54°
<AOE=72+54°=126°
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c)(OE si (OF determina <DOE
<DOE=<DOB+<BOE
<DOB=72/2=36°
<BOE=54°
<DOE=36+54=90°=>
Cele 2 semidrepte sunt perpendiculare
Explicație pas cu pas:
