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media aritmetica a patru nr naturale impare consecutiveeste 68.aflati cel mai mic nr?​

Răspuns :

n= 2k+1 adica impar

( 2k+1 +2k+3 + 2k+5 + 2k+7 )/4=68

8k + 16 = 272

8k=256

k=32

N1=2k+1=65

N2=67

N3=69

N4=71