Salut !
Răspuns:
a) 2(x + 3) <= x-5
2x + 6 <= x-5
2x-x<=-5-6
x <= -11
b) 3(x - 2) < 2(x + 1)
3x - 6 < 2x + 2
3x - 2x < 2 + 6
x < 8
c) 6(x - 1) >-4(x + 2)
6x - 6 > -4x - 8
6x + 4x > -8 + 6
10x > -2
x > -2/10
d) 9(x + 1) >= -7(x + 2)
9x + 9 >= -7x - 14
9x+7x >= -14 - 9
16x >= -23
× >= -23pe16