[tex]\it 6.\ \ Cu\ T.\ \angle\ 30^o \Rightarrow AB=\dfrac{BC}{2}=\dfrac{8}{2}=4\ cm\\ \\ \\ 8)\ \ BC=2\cdot AM=2\cdot10=20\ cm\\ \\ \\ 7)\ \ Fie\ \ell\ lungimea\ laturii\ triunghiului\ ABC.\\ \\ Din\ enun\c{\it t} \Rightarrow BD=BE=2\ell \Rightarrow \Delta EBD-isoscel\ \ \ \ \ (1)\\ \\ m(\hat B)=60^o\ \ \ \ \ (2)\\ \\ (1),\ (2) \Rightarrow \Delta EBD-echilateral.[/tex]
