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va rog mult am evaluare​

Va Rog Mult Am Evaluare class=

Răspuns :

Răspuns:

3. (2x+1) *(2-x)/ (x+2)(2-x)  = (4x-2[tex]x^{2}[/tex]+2 - x)/(2x-[tex]x^{2}[/tex]-2x+4)= [tex]\frac{3x-x^{2}+2 }{-x^{2} +4}[/tex]

4. a) [tex]\frac{6xy}{9x^{2} } = \frac{2y}{3x}[/tex]

b) [tex]\frac{x+3}{5x+15} = \frac{x+3}{5(x+3)}[/tex]= [tex]\frac{1}{5}[/tex]

c) [tex]\frac{x^{2}-4x+4 }{x^{2}-2x} = \frac{(x-2)(x-2)}{x(x-2)}[/tex]= [tex]\frac{x-2}{x}[/tex]