Răspuns:
scuze... dar nu mai stiu proportii derivate...
15) a,b,c € N
a+b+c=260
{a,b,c} d.p {3,4,6}==>
==>
[tex] \frac{a}{3 } = \frac{b}{4} = \frac{c}{6} = k[/tex]
k, diferit de 0==>
a=3k
b=4k
c=6k
a+b+c=260
3k+4k+6k=260
13k=260
k=260:13
k= 20==>
==>a=60
==>b=80
==>c=120
16)
[tex]p = \frac{nr.cazuri \: favorabile}{nr.cazuri \: posibile} [/tex]
p=probabilitatea
a) numar cazuri favorabile= 35 (bile albe)
numar cazuri posibile= 80 (total bile)
[tex] \frac{35}{80} = \frac{7}{16} [/tex]
b) numar cazuri favorabile= 45(bile negre)
numar cazuri posibile= 80(total bile)
[tex] \frac{45}{80} = \frac{9}{16} [/tex]
