[tex]\displaystyle\bf\\\frac{17}{3}\times\frac{-6}{19}+\frac{17}{3}\times\frac{8}{57}=\\\\\\=\frac{17}{3}\left(\frac{-6}{19}+\frac{8}{57}\right)=\\\\\\=\frac{17}{3}\left(\frac{-18}{~~57}+\frac{8}{57}\right)=\\\\\\=\frac{17}{3}\times\frac{-18+8}{57}=\\\\\\=\frac{17}{3}\times\frac{-10}{57}=\\\\\\=\frac{17\times(-10)}{3\times57}=\\\\\\=\boxed{\bf-\frac{170}{171}}[/tex]
