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Stiind ca DE=DF=30cm siAB=AC=BC=26cm iarPdef=Pabc determina EF​

Răspuns :

Răspuns:

P∆abc=3×AB=3×26=78cm

Pabc=Pdef=78cm

Inseamna ca EF=Pdef-(DE+DF)

EF=78-(30+30)

EF=78-60

EF=18cm