abc:cba= 3, restul 26
a-c=4=> a=4+c
abc=3•cba+26
100a+10b+c=3(100c+10b+a)+26
100a+10b+c=300c+30b+3a+26
97a=299c+20b+26
97(4+c) =299c+20b+26
388+97c=299c+20b+26
388-26=299c-97c+20b+26
362=202c+20b /:2
181=101c+10b => c=1=> a=5
181=101+10b=>b=8
abc=581
verificare: 581:185=3, rest 26
581=3•185+26
581=555+26 (A)
