Răspuns:
a=-6; b=-3.
Explicație pas cu pas:
ecuatia de gradul I, mx=n, are o infinitate de solutii numai daca m=0 si n=0.
(a-b)x-2=b-3x+1, ⇒(a-b)x+3x=b+1+2, ⇒(a-b+3)·x=b+3, deci
[tex]\left \{ {{a-b+3=0} \atop {b+3=0}} \right. ~~\left \{ {{b=-3} \atop {a+3+3=0}} \right. ~~\left \{ {{a=-6} \atop {b=-3}} \right.[/tex]
