Răspuns:
Explicație pas cu pas:
a) 3x+1<15 ca fractia sa fie supraunitara
3x<14 x<14/3 x∈N x∈{0,1,2,3,4}
b)
4x+3<21 4x<18 x<4,5 x∈N x∈{0,1,2,3,4}
6
a)2x+3<10 2x<7 x<3,5 x∈N x∈{0,1,2,3}
b) 3x+2<9 3x<7 x<2,(3) x∈N x∈{0,1,2}
7.
a)37/4=9,25
b)148/25=148×4/100=5,92
c) 14/9=1,(5)
d)157/33=4,(75)
e) 122/99=1,(23)
f) 56/45=1,2(4)
g)123/22=5,5(90)
8
a)8,4=84/10=42/5
b)15,625=15625/1000=625/40
c)3,12=312/100=78/25
d)1,(3)=1_1/3=4/3
e)1,(21)=1_21/99=1_7/33=40/33
f) 2,(36)=2_36/99=2_12/33=78/33
g)1,2(3)=1_(23-2)/90=1_21/90=1_7/30=37/30
h)0,6(27)=(627-6)/990=621/990=69/110
i)0,72(6)=(726-72)/900=654/900=218/300=109/150
