Răspuns:
Explicație pas cu pas:
1)
a)2y²-y=0 y(2y-1)=0 y1=0 y2=1/2
b)6x²-24=6(x²-4)=6(x-2)(x+2)=0 x1=2 x2=-2
c)2x²-4x-6=2(x²-2x-3)=2(x-3)(x+1) x1=3 x2=-1
d)9y²-24y+16=(3x-4)² x1,2=4/3
2
x²+bx+c=0
x1=-2 x2=3/4 S=x1+x2=3/4-2=(3-8)/4=-5/4
P=x1x2=-2×3/4=-3/2
4x²+5x-6=0
3
x²+17x+16=x(x+16)+(x+16)=(x+16)(x+1)=0 x1=-1 x2=-16⇒A={-16,-1}
A∩Q=A
