Răspuns:
a) AB=2√3 AC=4√2
[tex] {bc}^{2} = {ac}^{2} + {ab}^{2} \ \\ {bc}^{2} = {2 \sqrt{3} }^{2} + {4 \sqrt{2} }^{2} \\ bc = \sqrt{12 + 32} \\ bc = \sqrt{44} \\ bc = 2 \sqrt{11} [/tex]
b)BC=6√2 AB=4√3
[tex] {ac}^{2} = {bc}^{2} - {ab}^{2} \\ {ac}^{2} = {6 \sqrt{2}^{2} } - {4 \sqrt{3} }^{2} \\ ac = \sqrt{72 - 48} \\ ac = \sqrt{24} \\ ac = 2 \sqrt{6} [/tex]
c)BC=6√3 AC=2√11
[tex] {ab}^{2} = {bc}^{2} - {ac}^{2} \\ {ab}^{2} = {6 \sqrt{3}}^{2} - {2 \sqrt{11}}^{2} \\ ab = \sqrt{108 - 44} \\ ab = \sqrt{64} \\ ab = 8[/tex]
