Răspuns:
Explicație:
3. 10,2kg NH3=10200 g NH3
nr. molecule
MNH3= 14 +3=17------>17g/moli
-se afla nr. moli de NH3 din 10200 g NH3
n= m : M
n= 10200g : 17g/moli=600 moli NH3
1mol NH3---------6,023.10²³molecule NH3
600moli--------------x molecule
x= 600 . 6,023.10²³molecule =3613,8.10²³ molecule NH3
4.
a. n= m : M
n= 32g : 40g/moli=0,8 moli NaOH
b. n= 14,4 kg : 160kg/kmoli = 0,09 kmoli = 90 moli CuSO4
MCuSO4=64 +32 +4.16=160-------> 160g/moli
