Răspuns:
Explicație:
592 g Mg(NO3)2
O2
masa de Ca(OH)2
-se afla masa molara a celor doua subst.
M Mg(NO3)2 = 24 + 2.14 + 6. 16=148------->148g/moli
M Ca(OH)2 = 40 + 2.16 + 2= 74-------> 74g/moli
-se afla masa de oxigen din 592g Mg(NO3)2
148 g Mg(NO3 )2-------------96 g O
592g-------------------------------xg
x= 592 . 96 : 148=384 gO
- se afla masa de Ca(OH)2 care cuprinde 384 g O
74g Ca(OH)2------------32 g O
yg -----------------------------384 gO
y= 74 . 384 : 32=888 g Ca(OH)2
n= 888g : 74g/moli= 12 moli Ca(OH)2
