Răspuns:
Explicație pas cu pas:
(x+y)²+xy =-1
xy-x²-y²=-7 <=>
x²+2xy+y²+xy = -1
-x²+xy-y² = -7 <=>
x²+3xy+y² = -1
-x²+xy-y² = -7
____________
4xy = -8 => xy = -8:4 => xy = -2 =>
x²-6+y² = -1
-x²-2-y² = -7 <=>
x²+y² = 5
(x+y)² = x²+2xy+y² => (x+y)² = (x²+y²) + 2xy = 5-4 = 1 =>
x+y = ±√1 => I) x+y = -1 ; II) x+y = 1
I) x + y = -1 ; xy = -2 ; x²+y² = 5 =>
x = 1 ; y = -2 sau x = -2 ; y = 1
II) x + y = 1 ; xy = -2 ; x²+y² = 5 =>
x = 2 ; y = -1 sau x = -1 ; y = 2