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Dau Coroana .

Aratati ca 1+ 1/2+ 1/2^2+ 1/2^3+...+ 1/2^8 <2


Răspuns :

[tex]1 + (\frac{1}{2}) {}^{2} + ( \frac{1}{2} ) {}^{3} + ... + ( \frac{1}{2} ) {}^{8} < 2 \\ 1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + ... + \frac{1}{256} < 2 \\ \frac{511}{256} < 2 \\ 511 < 512[/tex]