ms = m + m.apa = 100+2 = 102 g sol.
CuSO4*5H2O = cristalohidrat in care doar CuSO4 este md-ul fata de care vom calcula c%
M.CuSO4*5H2O = 160+5x18 = 250 g/mol
250g cristaloh. ........................ 160g CuSO4
2 g cristaloh. ........................... md = 1,28 g CuSO4
=> md = 1,28, ms = 102g
=> c% = mdx100/ms
= 1,28x100/102 = 1,25%