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KMnO4+HCl =KCl +MnCl2 +Cl2+H2O
Egalare + număr de oxidare.


Răspuns :

Răspuns:

2KMnO4 +16HCl=> 2KCl+2MnCl2 + 5Cl2+8H2O

Mn+⁷-5 e=>Mn+²reducere agent oxidant ×2

Cl‐¹+2e=>Cl2⁰ oxidare agent reducator ×5

2Mn+⁷-10e=> 2 Mn+²

3Cl-¹+10e=> 3Cl2⁰