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calculati mediia geometrica a nr: a= 3supra 2radical din2 +1 si b= 3supra2radical din2-1​

Răspuns :

[tex]\sqrt{\frac{3}{2\sqrt{2}+1 } *\frac{3}{2\sqrt{2} -1} } = \sqrt{\frac{9}{8-1} } = \sqrt{\frac{9}{7} } = \frac{3}{\sqrt{7} } = \frac{3\sqrt{7} }{7}[/tex]

Coroana ?