a) <HBG CU <GBF
<ABH CU <FBE
<EBC CU <CBD
b)m<ABC = 180 GRADE
180-20-20=140 DE GRADE REZULTA CA M(<ABH)+M(<FBE)+M(< FBE)=140 DE GRADE 2X+2X+X=140 DE GRADE
5X=140 , X=28 DE GRADE DECI M(<EBC)=M(CBD)= 28 DE GRADE
M(<ABH)=M(<FBE)=2x28= 56DE GRADE
M(<ABD)=M(<ABC)+M(<CBD)=180 DE GRADE +28 DE GRADE= 208 GRADE