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Sa se rezolve inecuatiile:

a) x2-7x+12≥0;
b) –x2+4<0;
c) x2+x+1<0;
d)4x2-4x+1≥0.​


Răspuns :

a)

[tex]x^{2} -7x + 12 \geq 0\\(x-4)(x-3) \geq 0 \implies x \in (-\infty, 3]\cup[4, \infty)[/tex]

b)

[tex]-x^{2} + 4 < 0 \iff x^{2} - 4 > 0 \iff (x-2)(x+2) > 0 \implies x \in (-\infty, -2)\cup(2, \infty)[/tex]

c)

[tex]x^{2} + x + 1 < 0, \triangle = -1 -4(1)(1) = 1 -4 = -3 < 0 \implies x \in \O[/tex]

d)

[tex]4x^{2}-4x +1 \geq 0 \iff (2x-1)^{2} \geq 0 \iff x \in \mathbb{R}[/tex]