Răspuns:
b) se aduce la acelasi numitor 8 fiecare fractie
[tex]\frac{5x-1}{8}[/tex] - [tex]\frac{4(x+2)}{8}[/tex] + [tex]\frac{3*8}{8}[/tex]= [tex]\frac{2(3x-7)}{8}[/tex] - [tex]\frac{4x}{8}[/tex]
[tex]\frac{5x-1 -4x-8 +24}{8}[/tex]= [tex]\frac{6x-14-4x}{8}[/tex] x +15 = 2x- 14
2x-x= 15+14 x= 29
c) aducem la acelasi numitor 16
11 +4x-12 = 6- 4x +8 separam x
4x-1 = 14-4x 4x+4x= 14+1
8x= 15 x= 15/8
