[tex]AB=\sqrt{BC^{2}-AC^{2} } =\sqrt{45^{2}-27^{2} } =\sqrt{1296} =36\\sinB=\frac{27}{45}=\frac{3}{5} \\sinC=\frac{36}{45} =\frac{4}{5} \\cos B=\frac{4}{5}\\cosC=\frac{3}{5}\\tgB=\frac{27}{36} =\frac{3}{4} \\tgC=\frac{36}{27} =\frac{4}{3} \\ctgB=\frac{4}{3}\\ctgC=\frac{3}{4}[/tex]
Bafta!
