1)
Datele problemei:
msol = 600g
c = 5%
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c=md*100/ms => md = c*ms/100 = 5*600/100 = 30g MnCl2
mH2O = ms - md = 600-30 = 570 g H2O
2)
Datele problemei:
ms = 20g
c = 0,9%
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c=md*100/ms => md = c*ms/100 = 0,9*20/100 = 0,18g NaCl
mH2O = ms - md = 20 - 0,18 = 19,82 g H2O