Răspuns:
[(2^4)^2÷ 2^4+2^2014÷2^9]×3÷48×2^2001=
[2^8:2^4+2^(2014-9)]×3:48×2^2001=
[2^(8-4)+2^2005]×3:48×2^2001=
(2^4+ 2^2005)×3:48×2^2001=
(16+2^2005)×3:48×2^2001=
[(16+2^2005)×3]/48 ×2^2001=
(16+2^2005)/16×2^2001=
(16+2^2005)/2^4 ×2^2001=
(16+2^2005)×2^1997=
(2^4+2^2005)×2^1997=
2^4×2^1997+ 2^2005×2^1997=
2^2001+ 2^4002
Explicație pas cu pas:
