Explicație:
1.CaO+ H2O-》Ca(OH )2
MCaO=40+16=56kg/kmol
MCa(OH)2= 40+ 2×17=40+ 34=74kg/kmol
c=(md/ms)×100
md=c×ms/100=2×740/100= 148/10= 14,8 kg
mCaO(de pe ecuatie)= 56*14,8/74=11,04 kg
2. 100kg CaCO3 imp........80kg CaO pur
xkg.....................................11,04 CaO pur
x= 100*11,04/80= 13,8kg