Răspuns:
1)
{
int n,i,j,x,nr;
cout<<"n=";
cin>>n;
cout<<"x=";
cin>>x;
int a[n];
for(i=1;i<=n;i++)
{
cout<<"a["<<i<<"]=";
cin>>a[i];
}
for(i=1;i<=n;i++)
{
nr=0;
for(j=1;j<=a[i];j++)
if(a[i]%j==0)
nr++;
if(nr==x)
cout<<a[i]<<" ";
}
return 0;
}
2)
#include <iostream>
using namespace std;
int main()
{
int n,i,j,x,nr;
cout<<"n=";
cin>>n;
int a[n];
for(i=1;i<=n;i++)
{
cout<<"a["<<i<<"]=";
cin>>a[i];
}
for(i=n;i>=1;i--)
{
nr=0;
for(j=2;j<=a[i]/2;j++)
if(a[i]%j==0)
nr++;
if(nr==0)
{
cout<<a[i]<<endl;
for(x=i;x<n;x++)
a[x]=a[x+1];
break;
}
}
n--;
for(i=1;i<=n;i++)
cout<<a[i]<<" ";
return 0;
}
3)
{
int n,i,j,x;
cout<<"n=";
cin>>n;
int a[n],b[10]={0};
for(i=1;i<=n;i++)
{
cout<<"a["<<i<<"]=";
cin>>a[i];
while(a[i]!=0)
{
x=a[i]%10;
a[i]=a[i]/10;
b[x]++;
}
}
for(i=0;i<=9;i++)
if(b[i]>0)
cout<<i<<" ";
return 0;
}
Explicație:
Multumesc+5*+cel mai inteligent raspuns?
