Răspuns:
[tex]1) 3x^{2} -4x+3[/tex]
[tex]2) x=1; y=1[/tex]
Explicație pas cu pas:
[tex]1) (2x-1)^2 - (x-\sqrt{2} )(x+\sqrt{2})\\4x^2-4x+1-(x^2-2)\\4x^2-4x+1-x^2+2=3x^2-4x+3\\2) \left \{ {{2x-y=1}|*2 \atop {3x+2y=5}} \right. \\\left \{ {{4x-2y=2} \atop {3x+2y=5}} \right. \\-----(+)\\4x-2y+3x+2y=2+5\\7x=7=> x=1\\\\3x+2y=5\\3*1+2y=5\\3+2y=5\\2y=2\\y=1\\S:(x;y)=(1;1)[/tex]
