Răspuns:
Explicație:
1.
MZn(OH)2= 65 + 2.16 +2=99-------> 99g/moli
M CaO = 40 +16=56------> 56g/moli
M NaNO3= 23 + 14 + 3.16=85-------> 85g/moli
MMg3(PO4)2 = 3.24 + 2.31 + 8.16=262------> 262g/moli
2.
MCa(OH)2= 40 +2.16 +2=74-------> 74g/moli
n= m : M
n= 222g : 74g/moli= 3moli Ca(OH)2
3.
3moli Mg(OH)2
nr. molecule
M=24 + 2.16 +2=58-------> 58g/moli
1mol Mg(OH)2---------6,023.10²³ molecule
3moli----------------------------x
x= 3 . 6,023.10²³=18,069 .1`0²³molecule Mg(OH)2