1.
44,8 L V L n moli
C4H10 + 13/2O2 --> 4CO2 + 5H2O
22,4 13x11,2 4
=> V = 44,8x13x11,2/22,4 = 291,2 L
100% (L) aer .................. 20% (L) O2
v L aer ............................ 291,2 L O2
= 1456 L aer
=> n = 44,8x4/22,4 = 8 moli CO2
2.
256 g V L m g md g
CH4 + Cl2 --lumina--> CH3Cl + HCl
16 22,4 50,5 36,5
=> V = 256x22,4/16 = 358,4 L Cl2
=> m = 256x50,5/16 = 808 g CH3Cl
=> md = 256x36,5/16 = 584 g HCl
stim ca c% = mdx100/ms
ms = md + m.apa = 584+200 = 784 g
=> c% = 584x100/784 = 74,5%