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masa de mangan care conține 6,023•10 (la puterea 22) atomi este​

Răspuns :

[tex]M_{Mn}=55g/mol[/tex]

[tex]N_{A}=6,023*10^{23}[/tex] atomi/molecule per mol de substanta

6,023*10^22 atomi = 0,6023*10^23 atomi Mn

6,023*10^23 atomi Mn..............55g Mn

0,6023*10^23 atomi Mn..........x g Mn

x = 0,6023*10^23*55/6,023*10^23 = 5,5g Mn